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# Test Taking Strategies

#### Stormcrow309 (590240) writes | more than 6 years ago

0

Following a thread recently posted, binomal distribution answers the 'how many I need to get right' question. Say that I am a slacker and only want a 70% on a 40 question 4 answer, multiple choice test. For some odd reason, people would think that I would require to learn 18 questions.

40 * 70% = 28

Following a thread recently posted, binomal distribution answers the 'how many I need to get right' question. Say that I am a slacker and only want a 70% on a 40 question 4 answer, multiple choice test. For some odd reason, people would think that I would require to learn 18 questions.

40 * 70% = 28

40 * 25% = 10

28 - 10 = 18

However, if we follow binomal distribution...

f(x,n,p) = [n x]*p^x*(1-p)^(n-x) where x is number of trials, n is number of successes and p is chance of success.

f(40,0...7,.25)=.18

1-.18=.82

28-8=20

So, if I want at 70 or higher on my exam with a 82% chance of succeeding, I want to know 20 questions. Same principle says to make a 90, I need to know 28 questions, not 26.

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