Review: Green Lantern
If Hollywood is getting to the lesser-known superhero comics, I'd like to see The American made into a movie. http://en.wikipedia.org/wiki/The_American_(comics) It's darker and has more room for serious stuff. As well as fun....
Google x86 Native Browser Client Maybe Not So Crazy After All
32-bit browsers running on 64-bit windows can launch another 64-bit executable.
First Acoustic Black Hole Created
heisenberg: uncertainty in energy times uncertainty in time has a lower bound. what is the energy of the phonons? given the small time that heisenberg allows the virtual phonon pairs to exist, how far can the phonons travel? without actually working out the numbers, my seat of the pants guess is that the number of virtual phonon pairs for which one member crosses the acoustic event horizon will be vanishingly small.
Solving the Knight's Tour Puzzle In 60 Lines of Python
$ time python -c "import sys; sys.stdout.write((lambda size, sizesq, allp, openclose: ((lambda mkbrd, brd, mv, av, d, finished: ((lambda h: h(h, mkbrd(), 0, 0, 0)) (lambda h, b, r, c, v: [ lambda: ([ lambda:'', lambda: ((lambda nb, nv: d([lambda:h(h, nb, r-2, c-1, nv), lambda:h(h, nb, r-1, c-2, nv), lambda:h(h, nb, r-2, c+1, nv), lambda:h(h, nb, r-1, c+2, nv), lambda:h(h, nb, r+1, c-2, nv), lambda:h(h, nb, r+2, c-1, nv), lambda:h(h, nb, r+1, c+2, nv), lambda:h(h, nb, r+2, c+1, nv)]) ) (mv(b,r,c,v), v+1))] [av(b,r,c)]()), lambda: brd(b)][finished(v,r,c)]()) )) (lambda: [-1] * sizesq, lambda b: '\n'.join((''.join('%4d' % v for v in b[i:i+size])) for i in range(0,sizesq,size)) + '\n\n', lambda b, r, c, v: b[:r*size+c] + [v] + b[r*size+c+1:], lambda b, r, c: int(r >=0 and r = 0 and c 0)]())), lambda fl: ''.join(f() for f in fl)][allp], [lambda v,r,c: int(v==sizesq), lambda v,r,c: int(v==sizesq and r==0 and c==0)][openclose] ))) (int(sys.argv), int(sys.argv)*int(sys.argv), int(sys.argv), int(sys.argv)))" 6 0 1
0 7 4 13 2 29
5 12 1 30 23 14
8 35 6 3 28 31
11 18 9 24 15 22
34 25 20 17 32 27
19 10 33 26 21 16
arguments: the 6 is the size of the board, 0 means to print the first found rather than all, and the 1 means to look for a closed path rather than an open path.